Question

A radio station tower was built in two sections A and B. Tower is supported by wires from a point O. Distance between the base of the tower and point O is 36 m. From point O, the angle of elevation of the top of section B is 30° and the angle of elevation of the top of section A is 45°
a. What is the height of the section B ? b. What is the height of the section A ?​

Answer 1

Step-by-step explanation:

We will take two trianlge to solve this

question.

Step-by-step explanation:

In AAOD,

tan30°=AD/OD

AD=36/13=20.784m{It is the height of

section B]

Now in trianlge BOD,

tan 45º=BD/OD

So,BD=OD(as tan45°=1)

This, AB=BD-AD=36-20.784=15.216m{It is the height of section A}