Question

A radioactive atom moving with a
velocity of 0.25c. The atom emits a
particle that has a velocity of 0.9c
relative to the atom in the direction
of its motion. What is the velocity of
the particle as observed?
a.1.11c
b.0.940
c.0.50 c
d.0.01 c​

Answer 1

Answer:

0.94 c

Explanation:

this is PG trb physics 2017 question

Answer 2

Answer:

The velocity of the particle is 0.94 c

Option b is the correct answer.

Explanation:

We know,

$u = u + \frac{v}{1} + \frac{uv}{c2}$

The velocity of the ദ-particle relative to the atom in the direction of motion

$u`= 0.9 c$

and

$v = 0.25 c$

which is the velocity of redioactive atom relative to an experimenter.

$u = 0.9c + \frac{0.25c}{1} + 0.9c × \frac{0.25c}{c2} = 0.94c$

Thus 0.94c is the velocity of ദ-particle as observed by the experimenter.