Question

A radioactive contaminant gives an unfortunate 0.5 kg lab rat a dose of 1500 rem in just 1
minute. Assuming that the half life of the radioactive isotope in the contaminant is much longer than
1 minute, what would the activity (in Bq) of the contaminant be if the contaminant is a 5MeV alpha
emitter (RBE = 15)?

Answer 1

Answer:

The work needed to be done is 156187 J.

Given :

Initial velocity(u) = 30 km/h = 30 × 5/18 = 25/3 m/s.

Final velocity(v) = 60 km/h = 60 × 5/18 = 50/3 m/s

Mass = 1500 kg

To Find :

Work needed to be done = ?

Solution :

We know the formula to calculate the work done,

So by using it,

➠ Work done = 1/2mv² - 1/2mu²

➠ W = m/2(v²-u²)

➠ W = 1500/2(50/3²-25/3²)

➠ W = 156187 J

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➤ Additional information :

Work is done when a force that is applied to an object moves that object or body!!

The work is calculated by multiplying the force by the amount of movement of an object itself !!

Formula = f × d

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