A radioactive element forms its own isotope after 3 consecutive disintegrations. The particles emitted are(a) 3 β–particles(b) 2 β–particles and 1 α–particle(c) 3 β–particles and 1 α–particle(d) 2 α–particles and 1 β–particle
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Uranium is the answer
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Total number of disintegrations = 3
To form its own isotope atomic number (Z) should remain the same.
Thus, the emission of one α−particle and two β−particles will maintain the Z as same.
where α−particle =2He raise to the power 4 and β−particles= −1β0
Thus, the particles emitted will be 2 α–particles and 1 β–particle
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