Question

A radioactive nucleus of mass M emits a photon of
frequency n and the nucleus recoils. The recoil energy will
be
(a) Mc² – hn (b) h²n² / 2Mc²
(c) zero (d) hn

Answer 1

Answer:

Given,

Mass of nucleus =M

Frequency of photon =υ

Velocity of nucleus =V

2

Momentum of photon P=

λ

h

=

c

hν

From conservation of momentum

Initial momentum = final momentum

0+0=MV

2

+P

V

2

=

M

P

=

Mc

hν

Recoil energy E=

2

1

MV

2

=

2

1

M(

Mc

hν

)

2

=

2Mc

2

h

2

ν

2

Recoil energy E=

2Mc

2

h

2

ν

2

Answer 2

Answer:

(b) h²n² / 2Mc²

Explanation:

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