Question

a radioactive substance disintegrates into two types of daughter nuclei,one type with disintegration constant (lamda)1and other type with disintegration constant (lamda2). determine the half life of radioactive substances.

Answer 1

Answer:

Half life is given as

$T_{1/2} = \frac{ln2}{\lambda_1 + \lambda_2}$

Explanation:

As we know that radioactive substance disintegrate simultaneously into two products

so net rate of disintegration is given as

$-\frac{dN}{dt} = \lambda_1 N + \lambda_2 N$

so we have

$-\frac{dN}{dt} = (\lambda_1 + \lambda_2) N$

so we have

$\lambda = \lambda_1 + \lambda_2$

now half life is given as

$T_{1/2} = \frac{ln2}{\lambda}$

$T_{1/2} = \frac{ln2}{\lambda_1 + \lambda_2}$

#Learn

Topic : Radioactivity

https://brainly.in/question/8391264