Chemistry, asked by twin9, 11 months ago

a radioactive substance is found to have half life periods 100 sec. how long it will take to be reduced to it's 1/8 of the original

Answers

Answered by Tulsirani100

Suppose N is the original amount of radioactive substance.

After 1st half life
N/2

After 2nd half life
1/2(N/2)=N/4

After 3rd half life
1/2(N/4)
N/8

It means after 3 half lives the substance becomes 1/8

1 half life =100s
3 half lives =3(100)
=300s

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