Question

A radioactive substance Technetium-99 is also used by physicians to examine blood flow to
specific organs and assess organ function or bone growth. It has a very short half-life of about 6
hours. The fraction of this material that would remain after 30 hours will be-
a) 1/32
b) 1/5
c) 1/2
d) 4/5


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Answer 1

Answer:

option (a) is correct...

Put t = 30 and t1/2 = 6

and No is the initial quantity or value of sample...

So , after 30 hrs it will become 1/32 of it's initial value....

Hope you will understand it

Answer 2

Given : A radioactive substance Technetium-99 has a very short half-life of about 6 hours.  

To Find : The fraction of this material that would remain after 30 hours

1/32

b) 1/5

c) 1/2

d) 4/5

Solution:

Ley say initial Amount = A

after 6 hrs  = A/2

After 6 + 6 = 12 hrs = (A/2)/2 = A/4

After 12 + 6 = 18 hrs = (A/4)/2 = A/8

After 18 + 6 = 24 hrs = (A/8)/2 = A/16

After 24 + 6 = 30 hrs = (A/16)/2  = A/32  

= (1/32)A

Hence 1/32  fraction of this material that would remain after 30 hours

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