Question

A radioisotopes of silver has a half life of 20 minutes. What fraction of the original mass would remain after one hour​

Answer 1

Answer:

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Answer 2

Here in this case ,

T = 20 minutes

t = 60 minutes

Therefore ,

N/N⁰= (1/2)^n = (1/2)⁶⁰/²⁰ = (1/2)³ = 1/8

After one hour, 1/8th of the original mass would remain.

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