Question

A radius of a circle has endpoints (4 -1) and (8 2). What is the equation that defines the circle if its center is at the fourth quadrant?

Answer 1

Answer:

r²=(8-4)²+(2+1)²

r²=16+9

r²=25

r=5

(x-4)²+(y+1)²=25

x²+16-8x+y²+1+2y=25

x²+y²-8x+2y-8=0

Answer 2

Answer:

A.

Step-by-step explanation:

(x-8)²+(y-2)²=25

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