Question

A railroad car of mass 4000 kg with velocity of 2m/s slams into another railroad car of mass 6000kg which is at restand couples together. what is the combined speed of the railroad car after the collision

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Combined\:velocity=0.8\:m/s}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt : \implies Railroad \: car \: mass( m_{1}) = 4000 \: kg \\ \\ \tt: \implies Velocity \: of \: car( v_{1}) =2 \: m/s \\ \\ \tt : \implies Railroad \: car \: mass( m_{2}) = 6000 \: kg \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Combined \: velocity( v_{c}) =?$

• According to given question :

$\tt \circ \: Velocity \: of \: m_{2} = 0 \: m/s\\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies m_{1} v_{1} + m_{ 2 } v_{2} = ( m_{1} + m_{2}) v_{c} \\ \\ \tt: \implies 4000 \times 2 + 6000 \times 0 = (4000 + 6000) v_{c} \\ \\ \tt: \implies 8000 + 0 = 10000 \times v_{c} \\ \\ \tt: \implies v_{c} = \frac{8000}{10000} \\ \\ \green{\tt: \implies v_{c} = 0.8 \: m/s} \\ \\ \green{\tt \therefore Combined \: velocity \: is \: 0.8 \: m/s}$

Answer 2

Answer:

0.8m/s

Explanation:

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