Question

A railroad train travels forward along a straight track at 80.0 m/s for 1 000 m and then travels at 50.0 m/s for the next 1 000 m. What is the average velocity?

Answer 1

Answer:

1000m/80 m/s=12.5 seconds

1000 m/50 m/s=20 seconds

2000m/32.5 seconds=61.538462 m/s average velocity

Answer 2

Given : Railroad train travels 80.0 m/s for 1 000 m

            Travels at 50.0 m/s for the next 1 000 m.

To Find : Average Velocity

Solution :

Distance is 1,000 m and Speed is 80 m/s

Then,

Time = Distance/speed

Time taken in first part

$\[T = \frac{{1000}}{{80}} = 12.5\sec \]$

Now, For Time Taken in Second Part

Distance is 1,000 m, Speed is 50m/s

Time taken for second part is

$\[T = \frac{{1000}}{{50}} = 20\sec \]$

For Average Velocity ,

Average velocity = Total Distance/Total Time

Average velocity = $\[\frac{{2000}}{{32.5}} = 61.5m/s\]$

Hence Average Velocity is  61.5 m/s