A railway car of mass 20 tonnes moves with an initial speed of 54 km/hr. On applying brakes, a constant negative acceleration of 0.3 m/s is produced. 1) what is the breaking force acting on the car? 2) in what time it will stop? 3) what distance will be covered by the car before if finally stops?
Answers
Answered by
93
1 ton =1000 kg
mass of Railway =20000 kg
initial velocity = 54 km/hour(15m/s)
by applying brakes
final velocity of train will be zero.
acceleration= -0.3 m/s²
1] force =mass × accelaration.
force =20000 × 0.3
so force = 6000 Newtons.
•••••••••••••••••
2] using the formula v = u + a t
0 =15+(-0.3×t)
- 15 = - 0.3t
t = 50 seconds.
•••••••••••••••••
3] using the formula s = ut+1/2at² .
s = 15 x 50 +1/2 x 0.3 x 2500.
s = 750 + 750/2.
s = 750 +375.
s = 1125 metres.
PLEASE MARK IT AS A BRAINLIEST ANSWER.
mass of Railway =20000 kg
initial velocity = 54 km/hour(15m/s)
by applying brakes
final velocity of train will be zero.
acceleration= -0.3 m/s²
1] force =mass × accelaration.
force =20000 × 0.3
so force = 6000 Newtons.
•••••••••••••••••
2] using the formula v = u + a t
0 =15+(-0.3×t)
- 15 = - 0.3t
t = 50 seconds.
•••••••••••••••••
3] using the formula s = ut+1/2at² .
s = 15 x 50 +1/2 x 0.3 x 2500.
s = 750 + 750/2.
s = 750 +375.
s = 1125 metres.
PLEASE MARK IT AS A BRAINLIEST ANSWER.
Answered by
6
I hope you get the answer
Attachments:
Similar questions