Question

a railway carriage of mass 9000 kilogram moving with a speed of 36 km per hour collides with a stationary carriage of the same mass after the collision the carriage kit Kappal time move together Katli their common speed after collision what is the nature of the solution give reason for your answer​

Answer 1

Answer:

Explanation:

Mass of the cariage (mc) = 9000 kg = 90,00,000 gram

velocity of carriage (vc) = 35 km/hr = 9.7 m/s

Total momentum of carriage (p1) = mc vc = 9000000 x 9.7 = 87300000 kg.m.s-1

and,

Total momentum of carriage at rest (p2) = 0

Hence, total momentum= 87300000 kg.m.s-1+0= 87300000 kg.m.s-1

i.e. total momentum before collision = 87300000 kg.m.s-1......... (1)

Similarly,

Let us consider the commmon velocity of the both the carriage after collision be 'v',

So, total momentum of the system after collision= 9000000 .v +9000000 .v

or, total momentum after collision = 18000000.v............ (2)

Using principle of conservation of momentum, we get,

total momentum before collision = total momentum after collision

or, 18000000.v = 87300000

∴ v = 4.85 m/s ans

ans: This collision is inelastic collision.