Question

A railway engine of mass 100 tons is pulling a wagon of mass 80 tons with a force of 4500N.The resistance force acting is 1N per ton.The tension in the coupling between the engine and the wagon is (N refers to Newton).

Answer 1

Answer:

The answer is 2000 N

Explanation:

We know that

F = ma

Given data:

m1= 10,0000 Kg

m2 = 80, 000 Kg

F = 4500 N

For the current system we have

a = Fnet/ m1 +m2

a = 4500 / 10,0000 +80,000

a = 4500 / 180,000

a = 0.025 m/s2

Tension in the coupling

T =Mass of wagon x a

T = 80,000 x 0.025

T = 2000 N

Answer 2

Your answer is attached to the page.

Explanation:

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