a railway flat car has an artillery gun installed on it.the combined system has a mass M and moves with a velocity v.The barrel of gun makes an angle @ with the horizontal.A shell of mass m leaves the barrel at sped u relative to barrel in forward directon.find speed of car so it may stop after the firing is.solution
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If the angle of the barrel of the gun is taken as ‘theta’, as per the conservation of the linear momentum; the formula for finding the speed of the car is –
m(vcos(theta)+V)=MV, V= mvcos(theta)/(M-m),
where M = mass of the car, v = velocity of car’s movement and m = mass of the gun shell.
m(vcos(theta)+V)=MV, V= mvcos(theta)/(M-m),
where M = mass of the car, v = velocity of car’s movement and m = mass of the gun shell.
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Answer:
answer is Mvcos alpha/M+m
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