Question

A railway having travelled at 3/5 of its normal speed reaches its destination 2 hiurs 30 min late . In what time would the train reach its destination traveling at normal speed?

Answer 1

Answer:

90 minutes

Step-by-step explanation:

let , distance of destination traveling is D

and normal speed is v

so, distance= speed * time

therefore, D= 3v/5* 2hour 20minute

D= 3v/5 * 150minute

D= 90v

according to questions, 90v distance is covered by normal speed v

so ,time = distance/speed

time= 90v/ v

time= 90 minutes

Answer 2

Answer:

Three hours and 45 minutes