Question

a railway line and a road run parallel. every morning mr. sharma cycles to work along his road and meets a train travelling in the same direction at a junction. ine day ge was late by 25 min and meets the train 6 km before the junction.What was the speed of the train if mr. sharma cycled at an average speed of 12km/hr on that day?

Answer 1

Step-by-step explanation:

Suppose train daily starts vtt distance before the crossing and the cyclist starts from his house and covers 20t distance daily, the difference in starting points thus is vtt−20t. Now since he is late the train travels in time t2: vtt2+10=vtt and cyclist travels in time t2: 20t2+10=20t a distance vt(25/60)+vtt2=vtt−10 where t2 is the time cyclist travels after waking up. The cylist would travel a distance 20t2=20t−10, this on slving gives vt=120!!

Answer 2

Answer:

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