Question

A railway track runs parallel to a road until the bend brings the road to railway crossing.rohan rides to work along the road everyday at a constant speed of 10km/hr.he normally meets a train that travels in the same direction at the crossing.one day was late by 25 minutes and met the train 5km before the level crossing.can u figure d speed of d train.
If u answer u will be considered brainliest answer.!!!

Answer 1

Given that,

Speed of rohan = 10 km/hr

He normally meets a train that travels in the same direction at the crossing but one day he was late by 25 min and met the train 5 km.

We need to calculate the time reached at crossing by rohan

Using formula of time

$t=\dfrac{d}{v}$

Put the value into the formula

$t=\dfrac{5}{10}$

$t=\dfrac{1}{2}\ hr$

$t=30\ min$

We need to find the time of train travelled

Using given time and t

$t'=t-25$

Put the value into the formula

$t'=30-25$

$t'=5\ min$

The train will travel 5 km in 5 min.

We need to calculate the speed of train

Using formula of speed

$v=\dfrac{d}{t'}$

Put the value into the formula

$v=\dfrac{5}{\dfrac{5}{60}}$

$v=\dfrac{300}{5}$

$v=60\ km/hr$

Hence, The speed of train is 60 km/hr.