A railway train moving at the rate of 14.5m/s. it struck by a stone moving horizontally at right angle to the train with the velocity of 11m/s. find the magnitude and direction of the velocity with which the stone appears to meet the train.
Answers
Answered by
3
Answer:
Joule : SI system, erg:CGS system
Work = Force x Distance = Mass x Acceleration x Length = Mass x
(Time)
2
Length
×Length
Dimensions of work = [W]=[M
1
L
2
T
−2
]
∴a=1,b=2,c=−2.
Now
SI system CGS system
M
1
=1kg M
2
=1kg
L
1
=1m L
2
=1cm
T
1
=1s T
2
=1s
Here N
1
=1,N
2
=?
∴UsingN
2
=N
1
[
M
2
M
1
]
a
[
L
2
L
1
]
b
[
T
2
T
1
]
c
=1[
1g
1kg
]
1
[
1cm
1m
]
2
[
1s
1s
]
−2
=1[
1g
1000g
]
1
[
1cm
100cm
]
2
=10
7
∴N
2
=10
7
So 1J=10
7
erg
Answered by
0
Answer:
18.2m/s at an angle 142.8 with the direction of the motion of the train
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