A railway wagon of mass 2500 kg moving with a velocity of 36 km/hr has a head – on collision with a stationary wagon of mass 3000 kg. If the two wagons move together after collision, calculate their common velocity after collision.
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Answer:
AnswerM 1
=2000kg M 2
=3000kg and v 1
=18km/h=5m/s and v 2
=0
Let final common velocity be v
Using conservation of momentum-
(M 1 +M 2 )v=M 1v 1 +M 2v 2
⟹5000v=2000×5
⟹v=2m/s
Initial K.E.=K 1
= 21M 1 v12
= l212000×5 2
=25000J
Final K.E.=K 2
= 21 (M 1+M2 )v 2
= 215000×2 2
=10000J
Loss in K.E=ΔK=K 1 −K 2
=15000
=15kJ
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