Question

A rain drop of mass 2 g falls with constant
speed of 10 m/s. The frictional force
experienced by raindrop is​

Answer 1

Answer:

frictional force experienced by raindrop= 0.2kg m/s2

Answer 2

Answer:

first change 2g into kg

first change 2g into kg Now,

first change 2g into kg Now, 1g = 1/1000 kg

first change 2g into kg Now, 1g = 1/1000 kg then 2g= 2/1000 kg

first change 2g into kg Now, 1g = 1/1000 kg then 2g= 2/1000 kg = 0.002 kg

first change 2g into kg Now, 1g = 1/1000 kg then 2g= 2/1000 kg = 0.002 kg Now,

first change 2g into kg Now, 1g = 1/1000 kg then 2g= 2/1000 kg = 0.002 kg Now, force= m*a

first change 2g into kg Now, 1g = 1/1000 kg then 2g= 2/1000 kg = 0.002 kg Now, force= m*a where,

first change 2g into kg Now, 1g = 1/1000 kg then 2g= 2/1000 kg = 0.002 kg Now, force= m*a where, m is mass

first change 2g into kg Now, 1g = 1/1000 kg then 2g= 2/1000 kg = 0.002 kg Now, force= m*a where, m is mass a is acceleration

so,

put the values

put the values here,

put the values here, F = 0.002 * 10

put the values here, F = 0.002 * 10 = 0.02