A rain drop of mass m 1g is falling from a height of 1km hits the ground with a speed of 50m/s
calculate
(a) The loss of potential energy of the drop.
(b) The gain in kinetic energy of the drop.
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Here , m=1g=10−3kg
h=1km=1000m
g=10ms−2v=50ms−1
Loss of potential energy of the drop
=mgh=(103kg)(10ms−2)(1000m)=10J (i)
Hence, option (a) is correct.
Gain in kinetic energy of the drop
=12mv2=12×(10−3kg)(50ms−1)2=1.25J (ii)
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Answer:
the loss of potential energy of the drop
Explanation:
a rain of masd 1g is falling from a height of the loss of pontial energy of the drop
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