A rain drop starts from a cloud at a height of 100 m and is acted upon by a uniform accelation of 8 ms-2 on account of friction of air. Calculate, when and with what velocity, it will reach the ground level.
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Answer:
Explanation:
u=0m/s
a=8m/s^2
s=100m
since , s=ut+1/2at^2
100=1/2x8xT^2
or t^2=100x2/8
t=5seconds
v=u+at
v=0+8x5
v=40m/s
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