Question

A raindrop of diameter 4mm is about to fall on the groud calculate the pressure inside the raindrop​

Answer 1

Answer:

Pressure inside the raindrop is 1.01372 * 10⁵ Pa

Explanation:

Given,

A raindrop of diameter 4mm is about to fall on the groud.

To calculate: The pressure inside the raindrop.

Solution:

You have not written the full question. The values of Surface Tension(T) and atmospheric pressure must be given so as to find the pressure inside the rain drop as we will be using the concept of Surface Tension throughout the problem.

I'm supposing Surface Tesion to be 0.072 N/m.

and, Atmospheric pressure is obviously 1.013 * 10⁻⁵ N / m²

We have been given diameter into mm. We can find radius and convert it into it's SI unit.

i.e Radius (r) = 4/2 mm = 2 * 10⁻³ m

We know the formula that Pressure inside a rain drop is given as:

P = P₀ + 2T/r

where, P = Pressure inside a rain drop , T = surface tension

and r is radius , P₀ = atmospheric Pressure

here, P₀ = 1.013 * 10⁵ N/m²

Substituting the values,

P = 1.013 * 10⁵ * ( 2*0.072) / (2 * 10⁻³)

P = 1.01372 * 10⁵ Pa

Therefore, Pressure inside the raindrop is 1.01372 * 10⁵ Pa

Answer 2

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Explanation: