a raindrop of diameter4mm is about to fall on the ground calclulate inside the raindrop [surface tension of water T=0.072n/m,atmospheric pressure=1.013×100000n/m×m
Answers
Answered by
0
Answer:
dont know
Explanation:
yes
Answered by
2
Answer:
T=0.072N/m
d=4mm
∴r=
2
4
mm=2×10
−3
m
P
0
=1.013×10
5
N/m
2
To find :Pressure inside the raindrop (P
i
)
Formula:P
i
=P
0
+
r
2T
=1.013×10
5
+
2×10
−3
2×0.072
=1.013×10
5
+0.00072×10
5
=1.01372×10 rech 5pa
The pressure inside the raindrop is 1.01372×10 Rech 5 pa
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