a raindrop of diameter4mm is about to fall on the ground calclulate inside the raindrop [surface tension of water T=0.072n/m,atmospheric pressure=1.013×100000n/m×m
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Answer:
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Answer:
Pressure inside the raindrop is 1.01372 * 10⁵ Pa
Explanation:
Given,
A raindrop of diameter 4mm is about to fall on the groud.
To calculate: The pressure inside the raindrop.
Solution:
Surface Tesion = 0.072 N/m.
and, Atmospheric pressure is obviously 1.013 * 10⁻⁵ N / m²
We have been given diameter into mm. We can find radius and convert it into it's SI unit.
i.e Radius (r) = 4/2 mm = 2 * 10⁻³ m
We know the formula that Pressure inside a rain drop is given as:
P = P₀ + 2T/r
where, P = Pressure inside a rain drop , T = surface tension
and r is radius , P₀ = atmospheric Pressure
here, P₀ = 1.013 * 10⁵ N/m²
Substituting the values,
P = 1.013 * 10⁵ * ( 2*0.072) / (2 * 10⁻³)
P = 1.01372 * 10⁵ Pa
Therefore, Pressure inside the raindrop is 1.01372 * 10⁵ Pa