A raindrop of mass 1 gm falling from a height of 1km hits the ground with a speed of 50 m/s. Calculate 1. the loss of PE of the drop,2. gain in KE of the drop, 3. is the loss of PE equal to gain in KE? If not why?
Answers
Answered by
3
Answer:
Mass=1g(m)
Height=1km(h)
Speed=50m/s
g=10m/s2
The formula of potential energy mgh=1×10001×10×1×1000=10J
With speed 50m/s the loss of potential energy of the drop is 10J
Explanation:
plz mark my answer as the brainliest
Similar questions