A raindrop of mass 1 gm falling from a height of 1km hits the ground with a speed of 50 m/s. Calculate 1. the loss of PE of the drop,2. gain in KE of the drop, 3. is the loss of PE equal to gain in KE? If not why?
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Answer:
Mass=1g(m)
Height=1km(h)
Speed=50m/s
g=10m/s2
The formula of potential energy mgh=1×10001×10×1×1000=10J
With speed 50m/s the loss of potential energy of the drop is 10J
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