Math, asked by sahibnoor70, 3 months ago


(a) Raju bought 1600 bananas at 3.75 a dozen. She sold 900 of them at 2 for 1 and the
remaining at 5 for 2. Find his loss or gain per cent.
With answer-60%
5​

Answers

Answered by asodiyazeel6
0

Answer:

ANSWER

Sameer bought 1600→cl   3.75 a dozen

cost for which sameer bought 1600 bananas

=121600=3.75=1216×375=Rs500

He sold 900 bananas at Rs 1 for two bananas

Amount to which he sold 900 bananas =2900×1

Rs=450

The remaining 700 are sold at Rs 2 for five

Amount to which be sold 700 bananas =5700.2

Rs=280

Gain =(Actualcostsoldcost−Actualcost)×100

=(500450+280−500)×100=5230=46 %

Step-by-step explanation:

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Answered by jeevanmunegowd7
6

Answer:

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Step-by-step explanation:

Sameer bought 1600→cl   3.75 a dozen

cost for which sameer bought 1600 bananas

=  

12

1600

​  

=3.75=  

12

16×375

​  

=Rs500

He sold 900 bananas at Rs 1 for two bananas

Amount to which he sold 900 bananas =  

2

900

​  

×1

Rs=450

The remaining 700 are sold at Rs 2 for five

Amount to which be sold 700 bananas =  

5

700

​  

.2

Rs=280

Gain =(  

Actualcost

soldcost−Actualcost

​  

)×100

=(  

500

450+280−500

​  

)×100=  

5

230

​  

=46 %

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