Question

a) Raju sold an article at a loss of 8%. Had he bought it at 10%
less and sold for Rs. 80 more, he would have gained 20%. Find
the cost price of the article.​

Answer 1

Answer:

X+x+15+x+15=180

3x+30=180

3x=180-30

3x=150

x=150/3

x=50 degree

Therefore

=50 degrees

=50+15

=65 degrees.

Step-by-step explanation:

Answer 2

Answer:

Renu sold an article at a loss of 8 percent

Loss % = begin mathsize 16px style fraction numerator SP minus CP over denominator CP end fraction cross times 100 equals 8 end style

SP = 0.92CP ...(i)

she bought it at 10 percent less and sold it for rs 36 more.

New SP = Old SP + 36

90% of CP = 0.9CP

Profit = begin mathsize 16px style fraction numerator SP minus CP over denominator CP end fraction cross times 100 equals 20 end style

begin mathsize 16px style fraction numerator SP plus 36 minus 0.9 CP over denominator 0.9 CP end fraction cross times 100 equals 20 end style

Solving we get

SP = 1.08CP - 36 ...(ii)

From (i) and (ii)

we get CP = Rs. 225