A ram has taken loan from bank rs.42000.if company charges compound interst of rs.10% in first year and 10+1/2% in second year .how much ram will have to pay after two years
Answers
How does the concept of equal installments work for Compound interests? Well, in this case, the problem basically tells us that a certain sum of money is borrowed on compound interest for a certain period and it is returned with the help of equal installments.
Let us derive a formula where the amount is returned in two equal installments for a time period of two years.
Assume P to be the principal and r the rate of interest.
Step 1: P[{1+r/100}]= PI (amount of one year)
Step 2: New Principal
Now let X be the first installment. After giving the first installment, the principal value will change and the new principal will be = P1 – X
Step 3: Amount and Interest for the second year
Now the interest charged will be charged on this amount.
Amount at the end of second year is P2 = (P1 –X ){1+r/100}
compound interest examples
Step 4: Since the installments are equal, this new amount has to be equal to X.
Hence,
[P(1+r/100)-X][1+r/100]=X
On solving, we have
P (1+R/100)2-X (1+R/100)]= X
P (1+R/100)2]= X+X (1+R/100)
Divide both sides by (1+r/100)2
where X is the installment and n refers to the number of installments.
How does the concept of equal installments work for Compound interests? Well, in this case, the problem basically tells us that a certain sum of money is borrowed on compound interest for a certain period and it is returned with the help of equal installments.
Let us derive a formula where the amount is returned in two equal installments for a time period of two years.
Assume P to be the principal and r the rate of interest.
Step 1: P[{1+r/100}]= PI (amount of one year)
Step 2: New Principal
Now let X be the first installment. After giving the first installment, the principal value will change and the new principal will be = P1 – X
Step 3: Amount and Interest for the second year
Now the interest charged will be charged on this amount.
Amount at the end of second year is P2 = (P1 –X ){1+r/100}
compound interest examples
Step 4: Since the installments are equal, this new amount has to be equal to X.
Hence,
[P(1+r/100)-X][1+r/100]=X
On solving, we have
P (1+R/100)2-X (1+R/100)]= X
P (1+R/100)2]= X+X (1+R/100)
Divide both sides by (1+r/100)2
where X is the installment and n refers to the number of installments.