Question

a ramp for unloading and moving a truck has an angle of elevation of 30°. if the top of the ramp is 0.9m above the ground level then find length of ramp​

Answer 1

Answer:

length of ramp is 1.8 m

Step-by-step explanation:

AC = Hypotenuse side

AB = Opposite side

BC = Adjacent side

                  sin θ = opposite side/hypotenuse side

                  sin 30° = AB/AC

                     1/2 = 0.9/AC  

                     AC = 0.9 x 2  

                     AC = 1.8 m

Answer 2

Length of the ramp is 1.8 m

Step-by-step explanation:

Given:-

Refer to the attached figure.

Angle of elevation ($\angle ACB$) = $30 \ degree$

Height of the ramp (side AB) = 0.9 m

To find:- Length of the ramp (side AC) = ?

Solution:-

From the attached figure we can see that,

Angle of elevation is $\angle ACB =30\ degree$

Height of the ramp is side AB = 0.9 m

Now,

$sin\theta=\frac{opposite}{hypotenuse}$

$sin30=\frac{side AB}{side AC}$   -------------------------------(refer figure)

$\frac{1}{2} =\frac{0.9}{side AC}$          --------------------------(since $sin30 = \frac{1}{2}$ and side AB= 0.9 m )

$side AC = 0.9\times 2$

$side AC = 1.8 m$

Therefore length of the ramp is 1.8 m