a)Ramu's rectangular garden has length = 2x, breadth = 3y, Perimeter = 26 m
b)Raju's rectangular garden has length = 4x, breadth =5y,perimeter = 46 m
i) What is the Area of Ramu's rectangular garden
a) 54 m2 b) 48m2 c) 36m2 d) 72m2
ii) What is the Area of Raju's rectangular garden [
a) 140m2 b) 120m2 c) 150m2 d) 160m2
iii) Sum of the areas of two rectangular gardens is
a) 156m2 b) 188m2 c) 204m2 d) 332m2
iv) Find (x + y)2
a) 30 b) 35 c) 45 d) 25
v) The sum of lengths of two rectangular gardens is
a) 14m b) 12m c) 16m d) 18m
Answers
Step-by-step explanation:
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Given : Ramus rectangular garden has length = 2x, breadth = 3y, Perimeter=26
Raju's rectangular garden has length = 4x, breadth - 5y, perimeter 46 m
To Find : Area of Ramu's rectangular garden
Area of Raju's rectangular garden
areas of two rectangular gardens
Solution:
Perimeter of rectangle = 2 ( length + breadth )
Area of rectangle = length * breadth
Ramus rectangular garden has length = 2x, breadth = 3y, Perimeter=26
=> 2 ( 2x + 3y) = 26
=> 2x + 3y = 13 Eq1
Raju's rectangular garden has length = 4x, breadth - 5y, perimeter 46 m
=> 2 (4x + 5y) = 46
=> 4x + 5y = 23 Eq2
2* Eq1 - Eq2
=> y = 3
2x + 3(3) = 13 => x = 2
Ramus rectangular garden has length = 4, breadth = 9,
Area = 4 x 9 = 36 m²
Raju's rectangular garden has length = 8, breadth 15
Area = 8 x 15 = 120 m²
Area of both = 36 + 120 = 156 m²
(x + y)² = (2 + 3)² = 5² = 25
sum of lengths of two rectangular gardens is 4 + 8 = 12 m
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