A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240. If we want to provide a 95% confidence interval for the SAT scores, the degrees of freedom for reading the critical values of "t" statistic is
Answers
Given : A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240. we want to provide a 95% confidence interval for the SAT scores,
To Find : the degrees of freedom for reading the critical values of "t" statistic is
Solution:
Degrees of Freedom:
the maximum number of logically independent values,
that have the freedom to vary, in the data sample
Degrees of Freedom: is generally 1 less than the number of samples
Here number of samples = 64
Hence Degrees of Freedom = 64 - 1 = 63
So degree of freedom = 63
60 is closer to 60 hence 60 can be used from t table
However for such high number of sample , z score/ table can also be used.
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