Math, asked by f2020231048, 4 months ago

a random variable is normally distributed with a mean of 25 and a standard deviation of 5.a. what value will be exceeded 10% of the time. b.what value will be exceeded 85% of the time

Answers

Answered by Ikonikscenario7122
0

Answer:

P(z>z')=0.15\to P(z<z')=0.85P(z>z

)=0.15→P(z<z

)=0.85

From z-table:

z'=1.04z

=1.04

x'=20+(1.04)4=24.16x

=20+(1.04)4=24.16

b)

P(z>z')=0.75\to P(z<z')=0.25P(z>z

)=0.75→P(z<z

)=0.25

From z-table:

z'=-0.67z

=−0.67

x'=20+(-0.67)4=17.32x

=20+(−0.67)4=17.32

c)

P(z<-z')=0.2, P(z>z')=0.2P(z<−z

)=0.2,P(z>z

)=0.2

From z-table:

P(z<-0.84)=0.2005P(z<−0.84)=0.2005

z'=0.84z

=0.84

x'_1=20+(-0.84)4=16.64x

1

=20+(−0.84)4=16.64

x'_2=20+(0.84)4=23.36x

2

=20+(0.84)4=23.36

d)

P(z<z')=0.25P(z<z

)=0.25

Thus, this is the same value as in the part b).

x'=17.32x

=17.32

Step-by-step explanation:

Similar questions