Question

a random variable x has the following probability distribution find the value of k

Answer 1

Answer:

Answer:

Solution:

(i) Cost of white-washing the dome from inside = Rs 4989.60

Cost of white-washing 1m2 area = Rs 20

CSA of the inner side of dome = 498.96/2 m^2 = 249.48 m^2

(ii) Let the inner radius of the hemispherical dome be r.

CSA of inner side of dome = 249.48 m^2 (from (i))

Formula to find CSA of a hemi sphere = 2πr^2

2πr2 = 249.48

2×(22/7)×r2 = 249.48

r^2 = (249.48×7)/(2×22)

r^2 = 39.69

r = 6.3

So, radius is 6.3 m

Volume of air inside the dome = Volume of hemispherical dome

Using formula, volume of the hemisphere = 2/3 πr^3

= (2/3)×(22/7)×6.3×6.3×6.3

= 523.908

= 523.9(approx.)

Answer: Volume of air inside the dome is 523.9 m^3.

Answer 2

Answer:

Answer

As we know that ∑P(X)=1

⟹0.1+k+0.2+2k+0.3+k=1⟹k=0.1⟹10k=1

last one Brainlest please