Question

a random variable x has the following probability distribution,
${10k}^{2} + 9k$
Find K​

Answer 1

Answer:

Sum of all probabilities must be equal to 1

So we get K+2K+2K+3K+K

2

+2K

2

+7K

2

+K=1

⇒10K

2

+9K=1

⇒K=−1,

10

1

But probability cannot be negative , therefore the value of K=

10

1

The mean is 1.K+2.2K+3.2K+4.3K+5K

2

+6.2K

2

+7.7K

2

+7K

=30K+66K

2

=3+0.66=3.66

P(0<x<5)=P(x=1)+P(x=2)+P(x=3)+P(x=4)=K+2K+2K+3K=8K=0.8

Step-by-step explanation:

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Answer 2

Answer:

This is your answer

Step-by-step explanation:

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