Question

A random variable X takes values 1,2,3,.......... with probability mass function
function r= 1, 2, 3, ......... Find the value of 2.​

Answer 1

Answer:

hope it will help y ok u..

Step-by-step explanation:

,P(X≥n)=k=n∑∞P(X=k)=1−qpqn=qn

P(X≥m+n∣X≥m)=P(X≥m)P(X≥m+n)=qmqm+n=qn

P(X=m+n∣X≥m)=P(X≥m)P(X=m+n)=pqn.

HOPE IT WILL HELP YOU PLESE MARK IT AS BRIANLIST ANS AND FOLLOW ME

Answer 2

Answer:

ln2

Step-by-step explanation:

According to the question A random variable X takes values 1,2,3,..

with probability mass function

$\frac{\lambda^{r} }{r!}$ , r= 1, 2, 3,

So, ∑ $\frac{\lambda^{r} }{r!}$ = 1 , r = 1,2,3, ..

=> ∑ (r = 0,1,..) $\frac{\lambda^{r} }{r!}$  -  1 = 1

=> $e^{\lambda}$ = 2

=> $\lambda = ln2$