Question

a ratio of a adaughter's age her father's is 2 ratio 5 . 4 years ago their ratio was 1:5 . find the present age ?​

Answer 1

Step-by-step explanation:

let present age of daughter be x and present age of her father be y

x/y = 2/5

5x = 2y

5x - 2y = 0 ____ 1

before 4 years her age is x - 4

and her father's age is y - 4

therefore x - 4 / y - 4 = 1 / 5

y - 5 = 5x - 20

y - 5 + 20 = 5x

y + 15 = 5x

5x + y = -15 ____ 2

subtracting eq 2 from eq 1

5x - 2y = 0

- 5x + y = - 15