Question

a rational number is in the form of p/q in which q not equal to 0 and p q are positive integers which represent 0.134bar is ( bar on 34 only)​

Answer 1

Answer:

$\frac{133}{990}$

Step-by-step explanation:

let x=0.134343434

let x=0.134343434so 10x=1.343434---------->eq(1)

let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)

let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)(2)-(1)

let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)(2)-(1)990x=133

let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)(2)-(1)990x=133$x = \frac{133}{990}$

Answer 2

Answer:

133/990

Step-by-step explanation:

let x=0.134343434

let x=0.134343434let x=0.134343434so 10x=1.343434---------->eq(1)

let x=0.134343434let x=0.134343434so 10x=1.343434---------->eq(1)let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)

let x=0.134343434let x=0.134343434so 10x=1.343434---------->eq(1)let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)(2)-(1)

let x=0.134343434let x=0.134343434so 10x=1.343434---------->eq(1)let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)(2)-(1)let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)(2)-(1)990x=133

let x=0.134343434let x=0.134343434so 10x=1.343434---------->eq(1)let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)(2)-(1)let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)(2)-(1)990x=133let x=0.134343434so 10x=1.343434---------->eq(1)100x=134.343434------------>eq(2)(2)-(1)990x=133

$x = 133 \div 990$