Math, asked by meeransaranjum, 2 months ago

a rationalising factor of
(∛9-∛3+1)
step by step any one please​

Answers

Answered by shriram7246
5

Answer:

cube root of 3+1

Step-by-step explanation:

we know that

(x^2-x+1)(x+)=x^3+1

Substituting, x= cu root (3); we obtain

( cu root (9) - cu root +(3)+1) ( cube root (3)+1

=《cu root (3》^2-cu root (3)+1) ( cube root (3)+1)

=3+1

=4

Accordingly

(cu root of 9- cu root of 3+1

=4 ( cube root (3)+1)

Hence, the rationalizing factor is (cube root(3)+1)

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