a rationalising factor of
(∛9-∛3+1)
step by step any one please
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Answer:
cube root of 3+1
Step-by-step explanation:
we know that
(x^2-x+1)(x+)=x^3+1
Substituting, x= cu root (3); we obtain
( cu root (9) - cu root +(3)+1) ( cube root (3)+1
=《cu root (3》^2-cu root (3)+1) ( cube root (3)+1)
=3+1
=4
Accordingly
(cu root of 9- cu root of 3+1
=4 ( cube root (3)+1)
Hence, the rationalizing factor is (cube root(3)+1)
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