Question

A ray of light deviates 15° away from normal on going from one medium to another
medium. If angle of refraction is 45° then refractive index of second medium with
respect to first medium is ​

Answer 1

Answer:

3 is the refractive index

Answer 2

$n=0.707$ is the refractive index of the second medium with respect to first.

Explanation:

Given:

• angle deviated away by the light when passing from one medium to another, $\Delta \theta=15^{\circ}$

• angle of refraction, $\angle r=45^{\circ}$

Therefore angle of incident:

$\angle i=\angle r-\Delta \theta$

$\angle i=45-15$

$\angle i=30^{\circ}$

Now from the Snell's law we have refractive index of the first medium with respect to second as:

$n=\frac{\sin i}{\sin r}$

$n=\frac{\sin 30}{\sin 45}$

$n=0.707$

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TOPIC: optical desity

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