a ray of light enter into benzene from air. if the refractive index of benzene is 1.50, by what percent does the speed of light reduce on entering the benzene?
Answers
Answered by
3
hey mate..!! ☺
Let c be speed of light in vaccum and v be speed of light in benzene.
Refractive index of benzene=1.5=speed of light in vaccum/speed of light in benzene.
c/v=1.5
v=2/3c
Percentage reduce in speed of light
=(c-v/c)*100
=(1/3)*100=33.33%
That's all
Mark me as the brainliest please..
Let c be speed of light in vaccum and v be speed of light in benzene.
Refractive index of benzene=1.5=speed of light in vaccum/speed of light in benzene.
c/v=1.5
v=2/3c
Percentage reduce in speed of light
=(c-v/c)*100
=(1/3)*100=33.33%
That's all
Mark me as the brainliest please..
Answered by
2
Answer : 33.33%
Explaination :
Refractive index of a medium is given by the relations : 1n2 = v1 / v2.
where v1 and v2 is velocity in medium 1 and 2 respectively.
1n2 = 1.5. Let v1 = c. Then:
v2 = c / 1.5 .
v1 - v2 = c/3.
Calculate the percentage reduction. You will get 33.33%
Similar questions