Question

a ray of light entering a glass of refractive index 1.41 at an angle of incidence of 45.By how many degrees light change direction while entering the glass.​

Answer 1

Answer:

sin45÷sinx=1.41

sinx=sin45÷1.41

sinx=1.41÷1.41\2

X =30

15 degree angle will be changed of the direction of light while entering into the glass.

Answer 2

31.2 degrees light change direction while entering the glass.​

The amount by which a light beam changes its direction when it enters a medium with a different refractive index depends on the angle of incidence and the refractive indices of the two media involved. According to Snell's Law, it asserts the following:

$n_1 \times sin(\theta_1) = n_2 \times sin(\theta_2)$

where

$\theta_1$ is the angle of incidence (measured from the normal to the surface) and $\theta_2$ is the angle of refraction,

$n_1$ and $n_2$ are the refractive indices of the two media (also measured from the normal).

In this instance, the angle of incidence of the light beam is 45 degrees, entering a glass with a refractive index of 1.41.

Since air is so near to the vacuum, we may assume that the medium outside the glass, such as the air, has a refractive index of 1.

Snell's Law may be used to determine the angle of refraction in this way:

$1 \times sin(45) = 1.41 \times sin(\theta_2)$

$sin(\theta_2)$ = sin(45) / 1.41

$\theta_2$ = arc sin(sin(45) / 1.41)

$\theta_2$ ≈ 31.2 degrees

Hence, the light changes direction by nearly equal to 31.2 degrees when entering the glass.

For similar question on ray of light

https://brainly.in/question/10254219

#SPJ3