Question

A ray of light enters a diamond from air if the refractive index of diamond is 2.42 by what percent does the speed of light reduces

Answer 1

Explanation:

Let speed of light initially v

when light passes through diamond

then speed =v\u=v\2.42

now

change in speed

v(1-1/2.42)= (1.42/2.42)v

%Decrease =(1.42/2.42)×100%

=58.67

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