Question

A ray of light enters flint glass from air.
The refractive index of flint glass with respect to air is 1.65, by what percent does the speed of light reduce on entering the flint glass

Answer 1

$\Large \bf Given :$

$\bf Refractive \: index \: of \: flint \: glass, \: η_{g} = 1.65$

$\Large \bf To \: Find :$

$\bf Speed \: of \: light \: in \: glass, v_{g}$

$\Large \bf Solution :$

$\bf We \: know \: that \: speed \: of \: light \: in \: air, c=3×10⁸m/s$

Now, by formula :

$\bf η_{g} = \dfrac{c}{v_{g}}$

$\bf \implies v_{g} = \dfrac{c}{η_{g}}$

$\bf \implies v_{g} = \dfrac{3 \times 10^{8}m/s}{1.65}$

$\bf \implies v_{g} = \dfrac{3}{1.65}\times 10^{8}m/s$

$\bf \implies v_{g} = \dfrac{3 \times 100}{165}\times 10^{8}m/s$

$\bf \implies v_{g} = \dfrac{\cancel{3} \times 100}{\times{\cancel{165}}_{55}}\times 10^{8}m/s$

$\bf \implies v_{g} = \dfrac{100}{55}\times 10^{8}m/s$

$\bf \implies v_{g} = 1.8181... \times 10^{8}m/s$

$\bf \implies v_{g} = 1.82 \times 10^{8}m/s \: (approx.)$

$\bf \therefore Speed \: of \: light \: in \: glass, v_{g} = 1.82 \times 10^{8}m/s \: (approx.)$