a ray of light enters into acetone from air. if the refractive index of acetone is 1.36,by what present does the speed of light reduce on entering the acetone ??
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Given,
Refractive index of acetone= 1.36
So,
Refractive index=
Speed of light in medium 1÷Speed of light in medium 2
Here,
Medium 1= Air
Medium 2= Acetone
Now,
1.36 = 3*10^8/S.I.M2
S.I.M2 = 3*10^8/1.36
S.I.M2 = 3*10^10/136
S.I.M2 = 2.2*10^9
Hope this helps you!
Refractive index of acetone= 1.36
So,
Refractive index=
Speed of light in medium 1÷Speed of light in medium 2
Here,
Medium 1= Air
Medium 2= Acetone
Now,
1.36 = 3*10^8/S.I.M2
S.I.M2 = 3*10^8/1.36
S.I.M2 = 3*10^10/136
S.I.M2 = 2.2*10^9
Hope this helps you!
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