Question

a ray of light enters into benzene from air if refractive index of benzene is 1.50 .by what percent does the speed reduce a entering the benzene
?​

Answer 1

it is reduced by 33.3%

Refractive index of benzene = 1.5

Speed if light = 3 * 10^8

v = 3* 10^8/ 1.5 = 2 * 10^8

speed reduced = 33.3...%

Answer 2

Answer:

33.3 % .

Explanation:

Given :

Refractive index of benzene = 1.50

We know :

Speed of light = 3 × 10⁸ m / sec

We know formula for n :

n = speed of light in vacuum / speed of light in benzene

n = c / v

1.5 = 3 × 10⁸ / v

v = 2 × 10⁸ m / sec

Now ,

Percentage ( % ) decrease = 1  × 10⁸ / 3  × 10⁸  × 100 %

% decrease = 33.3 % .