A ray of light enters into benzene from air. If the refractive index of benzene is 1.50, by what percent does the speed  of light reduce on entering the benzene?
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The Required Answer is 33%
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Given:
Refractive index = 1.50
Light enters benzene.
To find:
The reduction in the speed of the light.
Solution:
By formula,
Refractive index = c / v
Where,
c - speed of light in air
c = 3 * 10^8 m / s
v - speed of light in benzene.
v = c / Refractive index
Substituting,
We get,
v = 3 * 10^8 / 1.50
Hence, the speed of the light in benzene = 2 * 10^8 m / s
Difference in speeds = 3 * 10^8 - 2 * 10^8 / 3 * 10^8
Hence, the speed reduces by 33%
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