Question

A ray of light enters into benzene from air. If the refractive index of benzene is 1.50, by what percent does the speed

of light reduce on entering the benzene?

Answer 1

Answer:

33.3 %

Explanation:

Refractive Index = Speed of light in Air / Speed of light in medium

Speed of light in medium = Speed of light in air / Refractive index

=> Speed of light in medium = 3 × 10⁸ / 1.5

=> Speed of light in medium = 2 × 10⁸ m/s

So, Percentage  = ( Change in Speed / Speed of light in air ) × 100

=> Change in Speed = 3 × 10⁸ - 2 × 10⁸

=> Change in speed = 10⁸ ( 3 - 2 ) = 10⁸

=> Percentage  = ( 10⁸ / 3 × 10⁸ ) * 100

=> Percentage = ( 1 / 3 ) * 100

=> Percentage  = 33.34 %

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Answer 2

Answer:

33.3 % .

Explanation:

Given :

Refractive index of benzene = 1.50

We know :

Speed of light = 3 × 10⁸ m / sec

We know formula for n :

n = speed of light in vacuum / speed of light in benzene

n = c / v

1.5 = 3 × 10⁸ / v

v = 2 × 10⁸ m / sec

Now ,

Percentage ( % ) decrease = 1  × 10⁸ / 3  × 10⁸  × 100 %

% decrease = 33.3 % .